Printing alphabets using pointers

#include <stdio.h>

int main() {

char a[26];

char *ch;

for(int i = 0; i < 26 ; i++){

a[i] = 'A' + i;

}

ch = a;

for(int i = 0; i < 26 ; i++){

printf("%c ", *(ch + i));

}

}

Output:

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z